Optimal. Leaf size=110 \[ \frac{a \tan ^3(c+d x)}{3 d}+\frac{2 a \tan (c+d x)}{d}-\frac{a \cot (c+d x)}{d}+\frac{5 a \sec ^3(c+d x)}{6 d}+\frac{5 a \sec (c+d x)}{2 d}-\frac{5 a \tanh ^{-1}(\cos (c+d x))}{2 d}-\frac{a \csc ^2(c+d x) \sec ^3(c+d x)}{2 d} \]
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Rubi [A] time = 0.136468, antiderivative size = 110, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.259, Rules used = {2838, 2622, 288, 302, 207, 2620, 270} \[ \frac{a \tan ^3(c+d x)}{3 d}+\frac{2 a \tan (c+d x)}{d}-\frac{a \cot (c+d x)}{d}+\frac{5 a \sec ^3(c+d x)}{6 d}+\frac{5 a \sec (c+d x)}{2 d}-\frac{5 a \tanh ^{-1}(\cos (c+d x))}{2 d}-\frac{a \csc ^2(c+d x) \sec ^3(c+d x)}{2 d} \]
Antiderivative was successfully verified.
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Rule 2838
Rule 2622
Rule 288
Rule 302
Rule 207
Rule 2620
Rule 270
Rubi steps
\begin{align*} \int \csc ^3(c+d x) \sec ^4(c+d x) (a+a \sin (c+d x)) \, dx &=a \int \csc ^2(c+d x) \sec ^4(c+d x) \, dx+a \int \csc ^3(c+d x) \sec ^4(c+d x) \, dx\\ &=\frac{a \operatorname{Subst}\left (\int \frac{x^6}{\left (-1+x^2\right )^2} \, dx,x,\sec (c+d x)\right )}{d}+\frac{a \operatorname{Subst}\left (\int \frac{\left (1+x^2\right )^2}{x^2} \, dx,x,\tan (c+d x)\right )}{d}\\ &=-\frac{a \csc ^2(c+d x) \sec ^3(c+d x)}{2 d}+\frac{a \operatorname{Subst}\left (\int \left (2+\frac{1}{x^2}+x^2\right ) \, dx,x,\tan (c+d x)\right )}{d}+\frac{(5 a) \operatorname{Subst}\left (\int \frac{x^4}{-1+x^2} \, dx,x,\sec (c+d x)\right )}{2 d}\\ &=-\frac{a \cot (c+d x)}{d}-\frac{a \csc ^2(c+d x) \sec ^3(c+d x)}{2 d}+\frac{2 a \tan (c+d x)}{d}+\frac{a \tan ^3(c+d x)}{3 d}+\frac{(5 a) \operatorname{Subst}\left (\int \left (1+x^2+\frac{1}{-1+x^2}\right ) \, dx,x,\sec (c+d x)\right )}{2 d}\\ &=-\frac{a \cot (c+d x)}{d}+\frac{5 a \sec (c+d x)}{2 d}+\frac{5 a \sec ^3(c+d x)}{6 d}-\frac{a \csc ^2(c+d x) \sec ^3(c+d x)}{2 d}+\frac{2 a \tan (c+d x)}{d}+\frac{a \tan ^3(c+d x)}{3 d}+\frac{(5 a) \operatorname{Subst}\left (\int \frac{1}{-1+x^2} \, dx,x,\sec (c+d x)\right )}{2 d}\\ &=-\frac{5 a \tanh ^{-1}(\cos (c+d x))}{2 d}-\frac{a \cot (c+d x)}{d}+\frac{5 a \sec (c+d x)}{2 d}+\frac{5 a \sec ^3(c+d x)}{6 d}-\frac{a \csc ^2(c+d x) \sec ^3(c+d x)}{2 d}+\frac{2 a \tan (c+d x)}{d}+\frac{a \tan ^3(c+d x)}{3 d}\\ \end{align*}
Mathematica [B] time = 6.08636, size = 359, normalized size = 3.26 \[ \frac{5 a \tan (c+d x)}{3 d}-\frac{a \cot (c+d x)}{d}-\frac{a \csc ^2\left (\frac{1}{2} (c+d x)\right )}{8 d}+\frac{a \sec ^2\left (\frac{1}{2} (c+d x)\right )}{8 d}+\frac{5 a \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )}{2 d}-\frac{5 a \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )}{2 d}+\frac{13 a \sin \left (\frac{1}{2} (c+d x)\right )}{6 d \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )}+\frac{a \sin \left (\frac{1}{2} (c+d x)\right )}{6 d \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )^3}-\frac{13 a \sin \left (\frac{1}{2} (c+d x)\right )}{6 d \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )}+\frac{a}{12 d \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )^2}+\frac{a}{12 d \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^2}-\frac{a \sin \left (\frac{1}{2} (c+d x)\right )}{6 d \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^3}+\frac{a \tan (c+d x) \sec ^2(c+d x)}{3 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.106, size = 138, normalized size = 1.3 \begin{align*}{\frac{a}{3\,d\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{3}}}+{\frac{4\,a}{3\,d\sin \left ( dx+c \right ) \cos \left ( dx+c \right ) }}-{\frac{8\,a\cot \left ( dx+c \right ) }{3\,d}}+{\frac{a}{3\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}}-{\frac{5\,a}{6\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2}\cos \left ( dx+c \right ) }}+{\frac{5\,a}{2\,d\cos \left ( dx+c \right ) }}+{\frac{5\,a\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{2\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.1672, size = 143, normalized size = 1.3 \begin{align*} \frac{4 \,{\left (\tan \left (d x + c\right )^{3} - \frac{3}{\tan \left (d x + c\right )} + 6 \, \tan \left (d x + c\right )\right )} a + a{\left (\frac{2 \,{\left (15 \, \cos \left (d x + c\right )^{4} - 10 \, \cos \left (d x + c\right )^{2} - 2\right )}}{\cos \left (d x + c\right )^{5} - \cos \left (d x + c\right )^{3}} - 15 \, \log \left (\cos \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\cos \left (d x + c\right ) - 1\right )\right )}}{12 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.46833, size = 575, normalized size = 5.23 \begin{align*} \frac{32 \, a \cos \left (d x + c\right )^{4} - 18 \, a \cos \left (d x + c\right )^{2} - 15 \,{\left (a \cos \left (d x + c\right )^{3} - a \cos \left (d x + c\right ) -{\left (a \cos \left (d x + c\right )^{3} - a \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )\right )} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) + 15 \,{\left (a \cos \left (d x + c\right )^{3} - a \cos \left (d x + c\right ) -{\left (a \cos \left (d x + c\right )^{3} - a \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )\right )} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) + 2 \,{\left (a \cos \left (d x + c\right )^{2} + 2 \, a\right )} \sin \left (d x + c\right ) - 8 \, a}{12 \,{\left (d \cos \left (d x + c\right )^{3} - d \cos \left (d x + c\right ) -{\left (d \cos \left (d x + c\right )^{3} - d \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.21085, size = 200, normalized size = 1.82 \begin{align*} \frac{3 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 60 \, a \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) + 12 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + \frac{12 \, a}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1} - \frac{3 \,{\left (30 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 4 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + a\right )}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}} - \frac{4 \,{\left (27 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 48 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 25 \, a\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1\right )}^{3}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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